Course Schedule Ii
To solve this coding challenge, we need to determine the correct order to take the courses given certain prerequisites. This problem can be effectively approached using Topological Sorting of a Directed Acyclic Graph (DAG). Here are the steps and pseudocode to solve the problem.
Explanation
- Graph Representation:
- In-degree Calculation:
- Queue Initialization:
- Topological Sorting using BFS:
- Check for Cycles:
- Graph Representation and In-degree Initialization:
- Use a dictionary to represent the graph where each key is a course and its value is a list of courses that depend on it.
- Initialize an in-degree list where each index represents the in-degree of the corresponding course.
- Read Prerequisites:
- For each prerequisite pair [ai, bi], add ai to the adjacency list of bi.
- Increment the in-degree of ai.
- Queue Initialization:
- Create a queue and enqueue all courses with in-degree 0.
- Topological Sorting:
- While the queue is not empty, dequeue a course, add it to the result list.
- For each neighboring course, decrease its in-degree by 1.
- If the in-degree of any neighboring course becomes 0, enqueue it.
- Check Result:
- If the length of the result list equals the number of courses, return the result list.
- Otherwise, return an empty list indicating it's impossible to complete all courses.
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Each course can be represented as a node in a graph. A prerequisite (e.g., to take course 1, you must first complete course 0) can be represented as a directed edge from node 0 to node 1.
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Calculate the in-degree of each node, i.e., the number of edges incoming to a node. This helps us in identifying which nodes (courses) do not have any prerequisites and can be taken first.
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Initialize a queue and add all nodes (courses) with in-degree 0. These nodes represent courses that can be taken without completing any other courses.
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Use BFS (Breadth-First Search) to perform the topological sorting. Dequeue a node, add it to the result list, and decrease the in-degree of its neighboring nodes by 1. If in-degree of any neighboring node becomes 0, enqueue that node.
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If at the end, the result list contains all courses, then a valid order exists. If not, it means there is a cycle in the graph, making it impossible to complete all courses.
Detailed Steps in Pseudocode
Pseudocode
# Step 1: Initialize Graph and In-degree list
graph = {} # Dictionary to store adjacency list
in_degree = [] # List to store in-degree of each course
# Initialize graph and in-degree list to default values
for each course in range(numCourses):
graph[course] = [] # Each course has an empty list initially
in_degree[course] = 0 # In-degree is 0 initially
# Step 2: Build Graph & Calculate In-degrees
# Loop through all prerequisites to build graph and in-degree list
for prerequisite in prerequisites:
course = prerequisite[0] # Course to be taken
prerequisite_course = prerequisite[1] # Prerequisite course
graph[prerequisite_course].append(course) # Append course to adjacency list of prerequisite_course
in_degree[course] += 1 # Increase in-degree of the course
# Step 3: Initialize queue with nodes of in-degree 0
queue = [] # A queue to help perform BFS
for course in range(numCourses):
if in_degree[course] == 0: # If a course has no prerequisites
queue.append(course) # Add it to the queue
# Step 4: Execute BFS to get topological order
result = [] # List to store the order of courses
while queue is not empty:
current_course = queue.pop(0) # Dequeue the course from the front of the queue
result.append(current_course) # Add it to the result list
# Decrease the in-degree of neighbor nodes (dependent courses)
for neighbor in graph[current_course]:
in_degree[neighbor] -= 1
if in_degree[neighbor] == 0: # If in-degree becomes 0, add it to the queue
queue.append(neighbor)
# Step 5: Check if all courses are taken
if length of result list == numCourses:
return result # Return the order of courses
else:
return [] # Return an empty list indicating it's impvelopment.
By following these detailed steps, we can ensure that all possible prerequisites are met, and we derive a valid order for taking the courses, or determine if it is impossible to complete them all given the constraints and prerequisites.