Combination Sum Ii

Sure! Let's break down how to solve this coding challenge step by step with detailed explanations and pseudocode. To solve this coding challenge, we need to find all unique combinations of a given list of numbers (
candidates
) that sum up to a specified target number (
target
). Each number in
candidates
can only be used once in each combination, and we should avoid duplicate combinations in the result.
# Explanation
  1. Problem Understanding :
    • You are given a list of integers called
      candidates
      and a target integer called
      target
      .
    • The aim is to find all unique combinations in
      candidates
      where the numbers sum up exactly to the
      target
      .
    • Each number may be used only once in each combination.
    • It is crucial to handle duplicate values in
      candidates
      to avoid generating duplicate combinations in the result.
  2. Constraints :
    • The length of
      candidates
      can range from 1 to 100.
    • Each integer in
      candidates
      can range from 1 to 50.
    • The
      target
      value can range from 1 to 30.
  3. Approach :
    • Sorting : Sort the
      candidates
      list to make it easier to avoid duplicates and to facilitate the "breaking" of loops when a value exceeds the target.
    • Backtracking : Use a backtracking approach to build combinations incrementally. This involves:
      • Recursive Function : A function that will try to add each candidate to a current combination (path), then recurse to see if a valid combination can be formed.
      • Base Case : If the current target becomes zero, the current combination is valid and should be added to the results.
      • Skipping Duplicates : When considering a candidate, skip it if it's the same as the previously considered candidate (to avoid duplicates).
      Let's start with a very detailed explanation followed by the detailed pseudocode:
    # Detailed Steps in Pseudocode
    1. Sort the `candidates` list
    Sorting helps to streamline the process of skipping duplicates and breaking out of the loop early if a candidate exceeds the target during recursion.
    2. Initialize the result list
    This will store all the valid combinations found.
    3. Define the backtracking function
    This function will handle the recursive aspect of exploring potential combinations.
  4. Parameters :
    • start_index
      : This indicates the current index in
      candidates
      being considered.
    • current_path
      : A list keeping track of the current combination being built.
    • remaining_target
      : The remaining value needed to reach the target.
    4. Base Case
    If
    remaining_target
    is zero, add a copy of the current combination to the result because we've found a valid combination.
    5. Iterate over the candidates starting from `start_index`
    For each candidate:
  5. Check for Duplicates : Skip if the candidate is the same as the previous one to avoid duplicate combinations.
  6. Break if Candidate Exceeds Target : If the candidate is greater than the
    remaining_target
    , no point in considering further as the list is sorted.
  7. Recursive Call : Add the candidate to the current path and call the backtrack function with updated parameters.
  8. Pseudocode
                                                
    function combinationSum2(candidates, target):
    # Step 1: Sort the candidates list to handle duplicates and make breaking conditions easier
    sort(candidates)
    
    # Step 2: Initialize the result list
    result = []
    
    # Step 3: Define the backtracking function
    function backtrack(start_index, current_path, remaining_target):
    # Step 4: Base Case - If remaining_target is 0, store a copy of current_path in result
    if remaining_target == 0:
    result.append(copy_of(current_path))
    return
    
    # Step 5: Iterate over candidates starting from start_index
    for current_index from start_index to length of candidates:
    # Skip duplicate candidates to avoid duplicate combinations
    if current_index > start_index and candidates[current_index] == candidates[current_index - 1]:
    continue
    
    # Break if current candidate exceeds the remaining_target
    if candidates[current_index] > remaining_target:
    break
    
    # Choose the current candidate by adding it to current_path
    current_path.append(candidates[current_index])
    
    # Recur with updated parameters: move to next candidate and reduce the target
    backtrack(current_index + 1, current_path, remaining_target - candidates[current_index])
    
    # Un-choose the current candidate to backtrack
    current_path.pop()
    
    # Initialize the backtracking with initial parameters
    backtrack(0, [], target)
    
    # Step 6: Return the result
    return result
    
                                            
    Step-by-Step Explanation
  9. Initial Setup :
    • Sort the list of candidates.
    • Initialize an empty list
      result
      to store the valid combinations.
  10. Backtracking Function definition :
    • The
      backtrack
      function takes in three parameters:
      start_index
      ,
      current_path
      , and
      remaining_target
      .
    • If
      remaining_target
      is zero, it means we have found a valid combination; we make a copy of
      current_path
      and add it to
      result
      .
  11. Looping and Conditions :
    • We loop through each candidate starting from
      start_index
      .
    • Skip duplicates: If the current candidate is the same as the previous one and it's not the first time we are looking at it on this recursive level (i.e.,
      current_index > start_index
      ), continue to the next iteration.
    • Stop further exploration if the current candidate exceeds
      remaining_target
      .
    • Include the current candidate in
      current_path
      and recurse with updated target.
  12. Backtracking :
    • After recursive call, remove the last candidate from
      current_path
      to backtrack and explore other possibilities.
  13. Returning the Result :
    • Finally, return the
      result
      .
By following these steps and pseudocode, we ensure we handle duplicates correctly and efficiently find all unique combinations that sum to the target value. This method leverages sorting, backtracking, and prudent skipping of candidates to provide the solution.