Bulls And Cows
To solve this coding challenge, you need to determine how many digits your friend's guess has in common with your secret number, and classify those digits as either "bulls" (correct digit in the correct position) or "cows" (correct digit but in the wrong position).
Here, I'll describe the methodology in detail and provide pseudocode for you to follow.
Explanation
The "Bulls and Cows" game involves comparing two numbers:-
Bulls:
Count of digits that are the same in both
secret
guess
-
Cows:
Count of digits that are in both
secret
guess
-
Bulls
are the digits in your friend's
guess
secret
-
Cows
are the digits in your friend's
guess
secret
- The solution efficiently counts these using two passes over the inputs: one to find bulls and collect frequency counts, and another to compute cows from these counts. The result is then formatted as "xAyB".
Detailed Steps in Pseudocode
Step 1: Initialize Variables
First, you need counters for bulls and cows. You also need to keep track of the frequency of each digit (0-9) in bothsecret
guess
Step 2: First Pass to Count Bulls
Loop through each digit insecret
guess
Step 3: Collect Frequencies
For the digits that are not bulls, record their occurrences in frequency counters for both thesecret
guess
Step 4: Compute Cows
Loop through the frequency counters for digits (0-9). For each digit, the number of cows is the minimum value between the two frequency counters, as it indicates how many times this digit can be matched betweensecret
guess
Step 5: Format and Return the Result
Format the result as "xAyB", where x is the number of bulls and y is the number of cows.Pseudocode with Comments
# Initialize counters for bulls and cows
bulls = 0
cows = 0
# Initialize lists for frequency counting, one for secret and one for guess
secret_frequency = array of size 10 initialized to 0
guess_frequency = array of size 10 initialized to 0
# Iterate over each digit in the secret and guess
for i = 0 to length of secret - 1:
if secret[i] == guess[i]: # If digits are the same in both secret and guess
bulls += 1
else:
# Increment the frequency counts for non-bull digits
secret_frequency[secret[i]] += 1
guess_frequency[guess[i]] += 1
# Compute the number of cows based on frequency counts
for i = 0 to 9: # Since digits range from 0 to 9
cows += min(secret_frequency[i], guess_frequency[i])
# Construct the result string
result = bulls + "A" + cows + "B"
# Return the formatted result
return result
This pseudocode provides a detailed step-by-step guide to implement the solution for the "Bulls and Cows" challenge. It ensures you correctly identify and count bulls and cows and format the result appropriately.